Loading...

I restricted the question to normal children. So the children who have cystic fibrosis, that outcome is excluded, and so the denominator of your probability now drops to three, and since there are still two chances of having one copy of that gene, the probability is actually two-thirds. Now, that's the easy part. Here comes the interesting part. For bonus points, and maybe some nice little piece of art of mine, for anybody who can get this one, do you know a related, very famous problem that's exactly analogous to the one I just gave you? It's a very famous problem. If you can get it, and you can describe to me why